Find the slopes of the line and a line perpendicular to y= -x + 10

Answer 1

y= -x + 10

Recall y = mx + b where m is the slope and the y intercept is "b".

So the slope is -1, and the y intercept is 10.

A line perpendicular to y = -x + 10 would have its slope = +x,

so y = x + b where b is any real number.