J.R. S. answered 01/04/21
Ph.D. University Professor with 10+ years Tutoring Experience
If you look up calcium citrate, you'll see there are 3 Ca for each calcium citrate. There are also 2 citrates. So, the formula is Ca3(citrate)2 or Ca3(C6H5O7)2
The molar mass of calcium citrate = 498 g/mol
The amount of Ca in 1 mol = 3 x 40 g = 120 g
% Ca = 120 g / 498 g (x100%) = 24.1 % calcium
Use dimensional analysis to find the number of tables needed for 1.10 g of Ca
4.57x10-3 mol CaCitrate/tablet x 120 g Ca/mol CaCitrate = 0.548 g Ca per tablet
1.10 g Ca x 1 tablet / 0.548 g Ca = 2.00 tablets
If you wanted to use % composition, you could proceed as follows:
4.57x10-3 mol / tablet x 498 g / mol x 0.241 Ca = 0.548 g Ca per tablet
1.10 g Ca x 1 tablet /0.548 g Ca = 2.00 tablets