J.R. S. answered 01/04/21
Ph.D. University Professor with 10+ years Tutoring Experience
N2 + 3H2 ==> 2NH3 ... balanced equation
14 g N2 x 1 mol N2/28 g N2 x 2 mol NH3/mol N2 x 17 g NH3/mol NH3 = 17 g NH3
Izzy D.
asked 01/04/21J.R. S. answered 01/04/21
Ph.D. University Professor with 10+ years Tutoring Experience
N2 + 3H2 ==> 2NH3 ... balanced equation
14 g N2 x 1 mol N2/28 g N2 x 2 mol NH3/mol N2 x 17 g NH3/mol NH3 = 17 g NH3
Hello Izzy,
First, we need to create our balanced equation [Nitrogen gas is (N2) and hydrogen gas is (H2)]:
N2(g) + H2(g) --> 2NH3(aq)
Now we can use our equation and do stoichiometry to figure out how many grams of ammonia were produced.
14gN2 x (1molN2/28gN2) x (2molNH3/1molN2) x (17gNH3/1molNH3) = 17 grams of NH3 were produced.
I hope this helps!
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
J.R. S.
01/04/21