Tom K. answered 12/20/20
Knowledgeable and Friendly Math and Statistics Tutor
A subset of A has 3 of the k elements of B, so it has C(k, 3) combinations. Then, for the n-k elements not in B, each can be in the subset or not, so there are 2n-k possibilities. Thus, there are
C(k, 3)2n-k subsets of A that have 3 elements in B.