J.R. S. answered 12/19/20
Ph.D. University Professor with 10+ years Tutoring Experience
In the future, You should probably break these up to individual questions, or limit them to 2 or 3 question per post. I'll give you advice on how to do them, and you can actually carry out the procedure.
1). P1/T1 = P2/T2 with T in Kelvin; 1.02 atm/305K = P2/351K => answer in atm
2). %by mass = mass of solute/total mass(x100%) = 26.4 g / (26.4 g + 415 g) [x100%] = % by mass NaBr
3). 4.3x104 x 2.9x10-3 = 12.47x101 = 1.247x102 = 1.2x102 (2 sig.figs.)
4). BL base is one that accepts H+, so it would be HPO42-
5). 4.65 mol Al x 3 mol O2 / 4 mol Al = moles O2 needed
6). 2.55 mol HCl x 2 mol Al / 6 mol HCl x 27 g Al/mol Al = g Al needed