What is the equation of a line in slope intercept form that passes through (-2,2) and is Perpendicular to the graph of y=12x-3?

Answer 1

In an equation of the form y = mx + b, m is the slope so for y=12x - 3, 12 is the slope.

The slope of the line perpendicular to that line is that negative reciprocal of 12 or -1/12

so for the other line we now have y = -1/12 x + b and we just need to find b

we know the line passes through (-2,2), so we can substitute -2 for x and 2 for y in the above equation and solve for b:

2 = (-1/12)-2 + b

2 = 2/12 + b

2 = 1/6 + b

12/6 = 1/6 + b

b = 11/6

y = (-1/12)x + 11/6