△ABC has vertices at A(5,1), B(−3,1) and C(−2,5). Point D is located on the intersection of the altitude and AB, in such a way that D has coordinates at (−2,1). What is the area of △ABC?

Answer 1

Area = 16

Area = (1/2)bh = half base times height

base = 5--3 = 5+3 = 8

height or altitude = 5-1 = 4

Area = (1/2)8(4) = 32/2 = 16