Using the TI-84 (or you can use Poisson.dist in excel)
P(X=5) = Poissonpdf(4.7,5) = 0.1738
P(X=3) + P(X=4) = Poissonpdf(4.7,3) + Poissonpdf(4.7,4) = 0.1574 + 0.1849 = 0.3423
P(X>=3) = 1-P(X<=2) = 1 - Poissoncdf(4.7,2) = 1 - 0.1523 = 0.8477
Rovin R.
asked 12/17/20Suppose the number of presents that Santa Clause leaves under Christmas trees is Poisson distributed with a mean of 4.7 presents per house.
A) Find the probability that he leaves exactly five presents under a tree
B) Find the probability that he leaves three or four presents under a tree.
C) Find the probability that he leaves at least three presents under a tree
Using the TI-84 (or you can use Poisson.dist in excel)
P(X=5) = Poissonpdf(4.7,5) = 0.1738
P(X=3) + P(X=4) = Poissonpdf(4.7,3) + Poissonpdf(4.7,4) = 0.1574 + 0.1849 = 0.3423
P(X>=3) = 1-P(X<=2) = 1 - Poissoncdf(4.7,2) = 1 - 0.1523 = 0.8477
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