How many liters of pure water should be mixed with a 19​-L solution of 60​% acid to produce a mixture that is 70% ​water?

Answer 1

100W + 60(19) = 70(W+19) = 70W + 1330

30W = 1330 - 1140 = 190

W = 190/30 = 19/3 = 6 1/3 liters of pure water to get 70% water of 25 1/3 liters

which is 25.33.. liters of 30% acid

That's one third water plus 2/3 60% acid gives 70% water

that's a 1:2 combination which cuts the acid in half, 60 to 30