955 grams of water at 25.0 C is heated to 85.5 C. Calculate the amount for Q in Joules?

Answer 1

q = mC∆T

q = heat = ?

m = mass of water = 955 g

C = specific heat of water = (4.184 J/gº) ... this is a constant that you can look up

∆T = change in temperature = 85.5º - 25.0º = 60.5ºC

q = (955g)(4.184 J/gº)(60.5º) = 241,741 Joules = 242,000 J (3 sig. figs.)