Find an equation that passes through (2,1) and is parallel to 3x+7y=2

Answer 1

solve for y

7y = -3x +2

y = (-3/7)x + 2/7. slope = m = -3/7

general form is

y=(-3/7)x + b, plug in (2,1) to solve for b

1 = (-3/7)(2) + b

b = 1+6/7 = 13/7