Suppose an object is thrown upward with an initial velocity of 48 feet per second from a height of 120 feet. The height of the object t seconds after it is thrown is given by

Question

H(t)=-16t2 +48t+120

a. Find the average velocity in the first two seconds after the object is thrown.

b. Find the average velocity from 𝑡 = 2 to 𝑡 = 4

Answer 1

H' = -32t + 48 = velocity

H'(0) = 48

H'(2) = -64 + 48 = - 16

H'(2) =-16

H'(4) = -64

from 0 to 2, velocity goes from 48 to -16, it goes up and then down, mostly up though >0

from 2 to 4 velocity goes from -16 to -64 . all negative <0 velocity