Find the perimeter of △ABC with vertices A(−5, 4), B(4, −5), and C(−5, −5). Round your answer to the nearest hundredth. The perimeter of △ABC is about units.

Answer 1

BC =9

AC =9

AB = sqr(81+81) = 9sqr2 = about 9(1.414) = 12.73

perimeter = 9+9+12.73 = 30.73

AB is the hypotenuse of a right triangle with 2 sides each = 9