Find the coordinates of point P along the directed line segment AB so that AP to PB is the given ratio. A(4, 10), B(14, 15); 3 to 2 The coordinates of P are ( , ).

Answer 1

P(4+2sqr(27/5), 10+ sqr(27/5) = about P(8.64, 12.32)

the distance from A to B is sqr(100+25) = 5sqr3. (3/5)5sqr3 = 3sqr3 is the hypotenuse of a right triangle with sides s and 2s 27=s^2 + 4s^ = 5s^2 s^2 = 27/5, s = sqr(27/5) = sqr(5.4) = 2.32. 2x2.32 = 4.64. 4+4.64 = 8.64 = x value of P s+10 = 2.32 + 10 = 12.32 = y value of P