Mark M. answered 12/15/20
Tutor
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(278)
Mathematics Teacher - NCLB Highly Qualified
1 - sin2 x = 2 cos x
1 - (1 - cos2 x) = 2 cos x
cos2 x = 2 cos x
cos2 x - 2 cos x = 0
cos x (cos x - 2) = 0
Alexis A.
asked 12/14/20
Mark M. answered 12/15/20
Mathematics Teacher - NCLB Highly Qualified
1 - sin2 x = 2 cos x
1 - (1 - cos2 x) = 2 cos x
cos2 x = 2 cos x
cos2 x - 2 cos x = 0
cos x (cos x - 2) = 0
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