Tom K. answered 12/12/20
Knowledgeable and Friendly Math and Statistics Tutor
Let the variance of each roll be V
Then, var(X) = 10V, var(Y) = 10V, and cov(XY) = 8V, because there are 8 rolls in common - rolls 3-10
(To show explicitly, let x1 = r1+r2, x2=r3+r4+r5+r6+r7+r8+r9+r10, and y1 = r11+r12;
X = x1+x2; Y = x2 + y1
then, cov(X,Y) = cov(x1+x2,x2+y1) = cov(x1,x2) + cov(x1,y1)+cov(x2,x2)+cov(x2,y1) = 0 + 0 + 8V + 0 = 8V)
Then, ρ = cov(XY)/√(var(X)var(Y)) = 8V/10V = 4/5