NEED HELP NOW 2 C8H18 + 25 O2 --> 16 CO2 + 18 H2O Calculate the mass in grams of carbon dioxide produced from 11.2 g of octane (C8H18) in the reaction above.

Question

1. answer choice:
2. 46.2 g
3. 89.6 g
4. 34.5 g
5. 17.3 g

Answer 1

C₈H₁₈ molar mass is 114.23g/mol

CO₂ molar mass is 44g/mol

according to the balanced equation, mass ratio of C₈H₁₈/CO₂=2*114.23/(16*44)

11.2g C₈H₁₈ generates CO₂ 11.2*16*44/(2*114.23)=34.5g

Answer 2

Use the balanced equation and dimensional analysis to find the answer.

2C₈H₁₈ + 25O₂ ==> 16CO₂ + 18H₂O ... balanced equation

molar mass C₈H₁₈ = 114 g/mol

molar mass CO₂ = 44 g/mol

dimensiona analysis:

11.2 g C₈H₁₈ x 1 mol C₈H₁₈ / 114 g x 16 mol CO₂ / 2 mol C₈H₁₈ x 44 g CO₂/mol CO₂ = 34.5 g CO₂