J.R. S. answered • 12/12/20
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HF ==> H+ + F-
Ka = [H+][F-]/[HF] and Ka = 1x10-pKa = 1x10-3.4 = 7.24x10-4
7.24x10-4 = (x)(x) / (0.210 - x)
x2 = 1.5x10-4 - 7.24x10-4x
x2 + 7.24x10-4x - 1.5x10-4 = 0
x = 0.01189 M = [H+]
pH = -log [H+]
pH = -log 0.01189
pH = 1.92
J.R. S.
tutor
Did quadratic equation again and got x = 0.01197 so made the correction. Thanks.
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12/12/20
Rahul S.
Everything is right just little bit calculation problem it is 1.9212/12/20