Find DE to the nearest tenth, given D(-5,2) and E(0,4)

Answer 1

distance squared = sum of squares of the differences in x and in y

DE = sqr(25+4) = sqr29 = about 5.385 = 5.4 to nearest 10th

Plot the points and create a right triangle, with height 2 and base 5, with hypotenuse = sqr29 = distance of DE

Answer 2

Use the distance formula to CALCULATE the distance between two points.....

d = √(X₂-X₁)² + (Y₂-Y₁)²

For:

(X₁, Y₁) = (-5, 2)

(X₂, Y₂) = (0, 4)

d=√(0−(−5))2+(4−2)2

d=√(5)2+(2)2

d=√25+4

d=√29

d=5.385165