Jason N.

asked • 12/10/20

Leap year - methods

A common year in the modern Gregorian calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are:

1) The year must be divisible by 4

2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400

Some example leap years are 1600, 1712, and 2016.

Write a program that takes in a year and determines whether that year is a leap year.

Ex: If the input is:

1712

the output is:

1712 is a leap year.

Ex: If the input is:

1913

the output is:

1913 is not a leap year.

Your program must define and call the following method. The method should return true if the input year is a leap year and false otherwise.

public static boolean isLeapYear(int userYear)




import java.util.Scanner;

public class LabProgram {

/* Define your method here */

public static void main(String[] args) {
/* Type your code here. */
}
}


Patrick B.

source code uploaded to RESOURCES section under this link
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12/10/20

1 Expert Answer

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Patrick B. answered • 12/10/20

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