Ronielien C.
asked 12/10/20Chemistry Question
1.00 mole of sodium sulfate (Na2SO4) is dissolved in 10.0 L of water. What is the concentration of potassium ions in the resulting solution?
- A. 0.200 M
- B. 0.500 M
- C. 0.400 M
- D. 0.100 M
2 Answers By Expert Tutors
J.R. S. answered 12/10/20
Ph.D. University Professor with 10+ years Tutoring Experience
Na2SO4 ==> 2Na+ + SO42-
1 mol/10 L = 0.1 mol/L
0.1 mol/L Na2SO4 x 2 mol Na+/mol Na2SO4 = 0.2 M Answer (A) if it asked for concentration of sodium ion
(guessing potassium ion is a misprint/error)
James M. answered 12/10/20
Master Chemistry Instructor with a record of success for Students
1 mole Na2SO4/ 10 L = 0.1 M , Na+1 concentration would be 2 mol Na1+/ 10 L = 0.2 M
there are no potassium ions present
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Ronielien C.
why D? I thought it was A?12/10/20