Area enclosed by parabola

Question

The figure shows a graph of y= ax²+ bx + c. Suppose that the points (-h,y₀), (0,y₁), and (h,y₂) are on the graph. The area enclosed by the parabola, the x-axis, and the lines X = -h and x = h may be given by the formula below. Find the area enclosed by f(x)= x²+ 2x + 5, the x-axis, and the lines x = -4 and x = 4

area = h/3 (y₀+4y₁+y₂)

plz help

Answer 1

Weird question for algebra 1 or2

c= y1

a = 1

b = (y0 - y2)/h

Answer 2

Use the formula with h=4 and x₀=-4 and x₁=0 and x₂=4

Plug the x values into the expression to get the y values as below.

You should get (4/3)(13+5+29).