What is the expected osmotic pressure, in torr, of a 0.0100 M solution of NaCl in water at 25°C?

Answer 1

NaCl ==> Na+ + Cl- (2 particles per molecule of NaCl)

π = iMRT

π = osmotic pressure = ?

i = van't Hoff factor = 2 for NaCl (1Na+ and 1Cl-)

M = molarity = 0.100

R = gas constant = 0.0821 Latm/Kmol

T = temperature in K = 25 + 273 = 298K

Solving for π we have..

π = (2)(0.1)(0.0821)(298)

π = 4.9 atm