Hello, Aseel,
There is no diagram in the question showing the A and B electron transitions. Generally speaking, the further an electron moves between orbital energy levels, the greater the energy involved. In an emission spectrum, the electron's are moving from high to low energy levels and emitting the energy difference as light energy. The shorter the wavelength, the higher the energy. The 450nm band reflects the higher energy transition, so the line showing the greatest change in energy levels is likely the source of this emission.
Wavelength and frequency are related: c = λ · ƒ where c is the speed of light, lambda is the wavelength and f is the frequency.
Bob