
Mark M. answered 12/06/20
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
:Law of Cosines
b2 = 42 + 52 - 2(4)(5) cos 60°
Can you solve for b and answer?
LL I.
asked 12/06/20Consider a triangle which has side lengths a, b, and c, and angles ,
, and
, with
opposite the side of length a, and so on. If
,
, and
, what is b?
Mark M. answered 12/06/20
Mathematics Teacher - NCLB Highly Qualified
:Law of Cosines
b2 = 42 + 52 - 2(4)(5) cos 60°
Can you solve for b and answer?
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LL I.
I got the square root of 21!12/07/20