J.R. S. answered 12/06/20
Ph.D. University Professor with 10+ years Tutoring Experience
I would like to add to the previous answer from @Greg S. I agree with his entire solution except for the mechanism part. I'd like to offer an alternative answer. I believe the entire 3-step equation is purported to be the mechanism (not just step a, b, or c). So, I would suggest that the proposed mechanism is reasonable for the determined rate law, and my reasoning is as follows:
We should look at the step leading up to and including the rate limiting step. This would be steps (a) and (b in the proposed mechanism
(a) A + B <=k1,k-1=> X fast
(b) X + Y <=k2=> D slow
In (a), let k1 be the rate constant for the forward reaction, and let k-1 be the rate constant for the reverse rx.
We can then write k1[A][B] = k-1[x] and solving for [x] we have [x] = k1/k-1[A][B]
In (b) we have the rate = k2[X][Y] and substituting for [X] we have...
rate = k2k1/k-1[A][B][Y]
so this can be written as rate = k'[A][B][Y] which would be in agreement with the determined rate law
J.R. S.
12/06/20