The temperature of a 5.0 g sample of Aluminum increases from 25°C to 30°C. How many joules of heat energy were added? (Specific heat of Al = 0.90 J/gK)

Answer 1

The equation you want to use is q = mC∆T

q = heat = ?

m = mass = 5.0 g

C = specific heat = 0.90 J/gº

∆T = change in temperature = 5º (doesn't matter in ºC or K since it is a ∆)

q = (5.0 g)(0.90 J/gº)(5º) = 22.5 J = 23 J (2 sig. figs.)