16.3 g of an imaginary compound X is dissolved in enough water to produce 471.5 mL of solution. Molar mass of the compound X = 41 g/mol. Calculate the concentration of the solution (molarity M)

Answer 1

Molarity (M) = moles of solute / liters of solution

moles of solute = 16.3 g x 1 mol/41 g = 0.398 moles

liters of solution = 471.5 ml x 1 L/1000 ml = 0.4715 L

M = 0.398 moles / 0.4715 L = 0.843 M (3 sig. figs.)