Mohammad S. answered 12/04/20
Tutor
5.0
(83)
A professor with over 20 years of teaching/tutoring experience
y(x) = (x - 4) (x -(2-3i))(x - (2+3i)) = (x - 4)(x^2 - 4x +13) = x^3 - 8x^2 + 29x - 52;
Shwati N.
asked 12/04/20Mohammad S. answered 12/04/20
A professor with over 20 years of teaching/tutoring experience
y(x) = (x - 4) (x -(2-3i))(x - (2+3i)) = (x - 4)(x^2 - 4x +13) = x^3 - 8x^2 + 29x - 52;
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