Find the equation of a line parallel to y =2/5x-6,875,390 passing through (-10,6)

Answer 1

Forever, if you know the slope m (the coefficient multiplier of x in y=mx+b), or m is given or calculated and a point (x₀,y₀) that needs to be on the line

the you can form the line equation with

m=(y-y₀)/x-x₀)

in this case (2/5)=(y-6)/(x-(-10)),

2/5=(y-6)/(x+10)

y=(2/5)x+(2/5)*10+6

y=(2/5)x+10

Answer 2

The slope-intercept form of a straight line is:

y = mx + b

where m is the slope of the line and b is the y-intercept. Sio you need to find the specific values of ma and b for your line. A line parallel to y = (2/5) x - 6,875,390 will have the same slope, 2/5. So your equation so far is:

y = (2/5)x + b

To find b, the y-intercept, simply plug in the given point (-10,6):

y = (2/5)x + b

6 = (2/5)(-10) + b

Solve for b.