Suppose an object is thrown upward with an initial velocity of 48 feet per second from a height of 120 feet. The height of the object seconds after it is thrown is given by

Question

H(t)=-16t² +44t+120

Find the average velocity from 𝑡 = 2 to 𝑡 = 4 *

Answer 1

h(2) = 144'

h(4) = 40'

104' in two seconds equals 72 ft/sec

Answer 2

Maria,

To find the height at 2 seconds, just plug 2 in for t: h(2)=-16(2)² +44(2)+120 = 144 ft.

h(4)=-16(4)² +44(4)+120 = 40 ft.

Then just take the average of 144 and 40: (144+40)/2 = 92 ft.

I hope that helps, and let me know if you have any questions!

Have fun mathing!

Liz Z.