Given the following reaction:

Question

Mg(OH)₂ + 2HCl → MgCl₂ + 2H₂O

How many grams of MgCl₂ will be produced from 9.0 g of Mg(OH)₂?

Mg(OH)₂ = (58.31g/mole)

MgCl₂ = (95.21 g/mole)

Answer 1

Mg(OH)₂ + 2HCl ==> MgCl₂ + 2H₂O ... balanced equation

Using dimensional analysis and the stoichiometry of the balanced equation, we can write...

9.0 g Mg(OH)₂ x 1 mol Mg(OH)₂/58.31 g x 1 mol MgCl₂/mol Mg(OH)₂ x 95.21 g MgCl₂/mol = 15 g MgCl₂ (2 sf)