You will use 200 for this problem since this is asking for 11th graders, not all students.
P(Eng 2 or Eng 3) = P(Eng 2) + P(Eng 3) - P(Eng 2 and Eng 3)
= (40/200) + (115/200) - 0
= 155/200
= 0.775
The probability that an 11th grader will take either English 2 or English 3 is 0.775.
Note: Each student is only allowed to take one English class. No student can do more than one English class, which explains that one of the probabilities from above is mutually exclusive.