n = 20 balls in a jar (6 reds, 8 whites, and 6 yellows)
Let R be the event where you draw a red ball.
Let W be the event where you draw a white ball.
Let Y be the event where you draw a yellow ball.
P(R) = 6/20 = 3/10 = 0.3
P(W) = 8/20 = 2/5 = 0.4
P(Y or R) = P(Y) + P(R) - P(Y and R) = 6/20 + 6/20 - 0 = 12/20 = 3/5 = 0.6
The probability of drawing a red ball is 0.3. The probability of drawing a white ball is 0.4. The probability of drawing either a yellow ball or a red ball is 0.6.
Note: P(Y and R) is the probability of drawing a ball that is both yellow and red. This is a mutually exclusive event.