J.R. S. answered 12/02/20
Ph.D. University Professor with 10+ years Tutoring Experience
Ba(OH)2 + 2HCl ==> BaCl2 + 2H2O ... balanced equation for neutralization reaction
moles HCl present = 10.0 ml x 1 L/1000 ml x 0.02000 mol/L = 0.000200 moles HCl
moles Ba(OH)2 needed = 0.000200 mol HCl x 1 mol Ba(OH)2 / 2 mol HCl = 0.000100 moles Ba(OH)2 needed
volume Ba(OH)2 needed: 0.0100 mol/L (x L) = 0.000100 moles; x = 0.0100 L = 10.0 mls Ba(OH)2 needed