Chemisty Homework help

Question

What mass of solid anhydrous iron(II) chloride is needed to make 50.0 mL of a 0.100 M solution?

Answer 1

molar mass anhydrous iron (II) chloride, FeCl₂ = 126.8 g/mol

50.0 ml x 1 L/1000 ml x 0.100 mol/L x 126.8 g/mol = 0.634 g FeCl₂ needed