How many milliliters of a 6.00 M HNO3 solution are needed to prepare 2.75 L of a 1.75 M solution?

Question

How many milliliters of a 6.00 M HNO₃ solution are needed to prepare 2.75 L of a 1.75 M solution?

Answer 1

For such a dilution problem you can use V1M1 = V2M2

V1 = initial volume = ?

M1 = initial molarity = 6.00 M

V2 = final volume = 2.75 L

M2 = final molarity = 1.75 M

Substituting values we have...

(x L)(6.00 M) = ( 2.75 L)(1.75 M)

x = 0.802 L

Converting to mls, we have

0.802 L x 1000 ml / L = 802 mls