What is the molarity of a solution prepared by adding 5.08 grams of calcium chlorite, to enough water to prepare 125 mL of solution?

Question

What is the molarity of a solution prepared by adding 5.08 grams of calcium chlorite, to enough water to prepare 125 mL of solution?

Answer 1

Molarity = moles of solute / liters of solution.

solute = calcium chlorite = Ca(ClO)₂

molar mass Ca(ClO)₂ = 175 g/mol

moles of solute = 5.08 g x 1 mol/175 g = 0.0290 moles Ca(ClO)₂

Liters of solution = 125 ml x 1 L/1000 ml = 0.125 L

Molarity = moles / liters = 0.0290 moles/0.125 L = 0.232 M (3 sig. figs.)