J.R. S. answered 12/01/20
Ph.D. University Professor with 10+ years Tutoring Experience
2F2O2 + 2H2O ==> 4HF + 3O2 ... balanced equation
The ice is actually the H2O in the reactant side of the equation, so the question is actually asking "how many grams of FOOF are necessary to burn 3.0 g of water"?
Using the balanced equation and dimensional analysis, we can approach this problem as follows:
3.0 g H2O x 1 mol H2O/18 g x 2 mol FOOF/2 mol H2O x 70.0 g FOOF/mol = 11.7 g FOOF