If Ahmed has 16 dimes and nickels in his pocket, and they have a combined value of 125 cents, how many of each coin does he have?

Answer 1

Let x = number of nickels and y = number of dimes

x+y = 16 --> y = 16-x

5x+10y = 125 --> 5x + 10(16-x) = 125 --> 5x + 160 - 10x - 125

5x = 35

x = 7

y = 16 - 7 = 9

Ahmed has 7 nickels and 9 dimes