J.R. S. answered 11/28/20
Ph.D. University Professor with 10+ years Tutoring Experience
C6H12O6(aq) + 6O2(g) ==> 6CO2(g)+ 6H2O(l) ... BALANCED EQUATION
From the balanced equation, we see that it takes SIX moles of O2(g) to react with ONE mole C6H12O6
Using this mol ratio information, we can find the moles of O2 needed to react with 38.0 g of glucose and then convert that to grams of oxygen.
38.0 g C6H12O6 x 1 mol C6H12O6 / 180 g x 6 mol O2 / mol C6H12O6 = 1.27 moles O2 needed
1.27 mol O2 x 32 g O2/mol O2 = 40.6 g O2 needed