J.R. S. answered 11/21/20
Ph.D. University Professor with 10+ years Tutoring Experience
We must first find the number of calories it takes to heat 45 g of water from 22º to 51º
q = mC∆T
q = heat in calories = ?
m = mass = 45 g
C = specific heat of water = 1 cal/gº
∆T = 51º - 22º = 29º
q = (45 g)(1 cal/gº)(29º) = 1305 cal
Now we convert this to kcal:
1305 cal x 1 kcal/1000 cal = 1.305 kcal
Finally we convert this to kcal/g:
1.305 kcal/2.5 g of pretzel = 0.522 kcal/g = 0.52 kcal/g (2 significant figures)