The definition of a calorie is the amount of heat to raise the temperature of 1 g by 1 degree.

In the current problem the change in temperature isn't 1 degree but it is 92 - 38 = 54 degrees

The amount of water isn't 198 grams but it is 198 grams.

Thus the number of calories needed = 198 g x 54 degrees = **10,692 calories**

Looking at this in a more "scientific" manner and using the equation for heat, we can calculate calories as ....

q = mC∆T

q = heat in calories

C = specific heat of water = 1 cal/gº

∆T = change in temperature

q = (198 g)(1 cal/gº)(54º) = **10,692 calories**