J.R. S. answered 11/21/20
Ph.D. University Professor with 10+ years Tutoring Experience
Since the anion in all of the salt is Br-, we need only concern ourselves with the size (atomic radius) of the cation. Since all of the cations are in the same group (group 2), and since atomic radius decreases going UP within a group, we can arrange the cations from smallest to largest as follows:
Be < Mg < Ca < Sr < Ba
So, final order of LE from greatest to least would be
BeBr2 > MgBr2 > CaBr2 > SrBr2 > BaBr2