I can't figure out how to do this Trig function equation.

Question

sin^2 theta * cos theta = cos theta over the interval [0 degrees, 360 degrees)

answer is in degrees

Answer 1

If you divide both sides by cos theta you have

sin^2 theta = 1

sun theta = + or - 1 which would be at 90 and 270 degrees

Answer 2

sin^2 theta* cos theta = cos theta

sin^2 theta* cos theta - cos theta = 0

cos theta(sin^2 theta - 1) = 0

cos theta(-cos^2 theta) = 0

-cos^3 theta = 0

cos theta =0

cos theta =0 on [0 degrees, 360 degrees) at

90 degrees, 270 degrees