what is an equation of the line that passes through (2,-1) and is parallel to the line 2y+3x=8?

Question

Please give a step-by-step answer. Thanks!

Answer 1

2y + 3x = 8

2y = -3x + 8

y = -(3/2)x + 4

Use the point-slope formula: y - y₁ = m(x - x₁)

y - (-1) = -(3/2)*(x - 2)

y + 1 = -(3/2)x + 3

y = -(3/2)x + 2 → 2y = -3x + 4 → 2y + 3x = 4

Answer 2

2y + 3x = 8

2y = 8 - 3x

y = 4 - (3/2) x

= (-3/2)x + 4

The parallel line MUST have slope

-3/2 and eats (2,-1)

B = y - mx

= -1 - (-3/2)(2)

= -1 - (-3)

= -1 + 3

= 2

y = (-3/2)x + 2