∆LUV ≅ ∆TKY Angle VL = 9x + 8 Angle TK = 4x + 15 Angle LU = 9x - 5 Find the length of TK.

Answer 1

Angle LU (really <LUV) and angle TK (really angle TKY) are congruent because of corresponding parts of congruent triangles.

So m<TKY = m<LUV

4x + 15 = 9x - 5

20 = 5x

x = 4

m<TKY = 4x + 15 = 4(4) + 15 = 23