J.R. S. answered 11/17/20
Ph.D. University Professor with 10+ years Tutoring Experience
When given a problem like this and working with gases, it's usually a good idea to assume you have a volume of 1 liter, and then proceed from there. In this problem, the pressure is 747 torr, which we will convert to atm, and we'll convert 70ºC to Kelvin.
747 torr x 1 atm/760 torr = 0.983 atm
70ºC + 273 = 343K
Now, we can use the ideal gas law PV = nRT and solve for moles. Once we get out moles, we can calculate molar mass of UF6 and then density is simply mass/volume.
n = PV/RT = (0.983 atm)(1 L) / (0.0821 Latm/Kmol)(343K
n = 0.0349 moles UF6
molar mass UF6 = 352 g/mol
Since we have 0.0349 moles/L we convert that to gram / liter to get density:
0.0349 moles/L x 352 g/mol = 12.3 g/L = 0.0123 g/ml