what is the slope of a line perpendicular to the line whose equation is 4x-y=9. Fully reduce your answer.

Answer 1

Step 1: Put the equation into slope-intercept form: y = mx + b

where m is the slope and the point (0,b) is the y-intercept (the point where x=0)

4x - y = 9

y = 4x - 9 [ m=4, b is (0,9) ]

Slope of this line is 4.

Step 2: Remember that all of its perpendicular lines has a slope of (-1/m), that is the negative reciprocal of slope m.

Slope of all perpendicular lines is (-1/4).

Answer 2

4x - y = 9

-y = -4x + 9

y = 4x - 9

Perpendicular lines have opposite, reciprocal slopes. Since m = 4 in this equation, the slope of a line perpendicular to this one is -1/4.

Answer 3

1. First get this equation in slope-intercept form: Y = MX + B
2. Then the perpendicular slope will be the negative reciprocal of the M in the equation above.
3. so:
4. 4x-y = 9 in slope-intercept form would be
5. y = 4x - 9
6. The slope to a line perpendicular to that would be (-1/4)

does this make sense to you?