
Mike D. answered 11/16/20
Effective, patient, empathic, math and science tutor
You can approximate this with a normal distribution, mean 150 x 0.35, variance 150 x 0.35 x 0.65 (so standard deviation is square root of this)
So mean is 52.5, standard deviation 5.84
Then you need p (X>60)
On a TI-84
2nd vars
normalcdf
lower = 60
upper = 1e99
mean 52.5
standard deviation 5.84
hit paste
0.0995
For the exact answer you need to sum 150 C n 0.35^n 0.65^ (150-n) for n = 60, 61, ..., 150